From 73ab191d64477e4ef2ef921df19d099b5e4e9577 Mon Sep 17 00:00:00 2001 From: x0x7 Date: Tue, 3 Dec 2024 10:03:42 -0500 Subject: [PATCH] Add 2024/day3/problem2.md --- 2024/day3/problem2.md | 20 ++++++++++++++++++++ 1 file changed, 20 insertions(+) create mode 100644 2024/day3/problem2.md diff --git a/2024/day3/problem2.md b/2024/day3/problem2.md new file mode 100644 index 0000000..c857532 --- /dev/null +++ b/2024/day3/problem2.md @@ -0,0 +1,20 @@ +--- Part Two --- +As you scan through the corrupted memory, you notice that some of the conditional statements are also still intact. If you handle some of the uncorrupted conditional statements in the program, you might be able to get an even more accurate result. + +There are two new instructions you'll need to handle: + +The do() instruction enables future mul instructions. +The don't() instruction disables future mul instructions. +Only the most recent do() or don't() instruction applies. At the beginning of the program, mul instructions are enabled. + +For example: + +xmul(2,4)&mul[3,7]!^don't()_mul(5,5)+mul(32,64](mul(11,8)undo()?mul(8,5)) +This corrupted memory is similar to the example from before, but this time the mul(5,5) and mul(11,8) instructions are disabled because there is a don't() instruction before them. The other mul instructions function normally, including the one at the end that gets re-enabled by a do() instruction. + +This time, the sum of the results is 48 (2*4 + 8*5). + +Handle the new instructions; what do you get if you add up all of the results of just the enabled multiplications? + +Answer: + \ No newline at end of file